?!

If that was the case, f(x) = 1/x would be a continuous function at 0. But the limit from the right =/= limit from the left... so it's not a continuous function ?

No. That would mean if 1/0 is 0, then 0×0 would need to be 1, but that is not the case. Also if I say 0/0 is 0 then 0×0 is 0 would be right, but then I could also say 0/0 is 3 because 3×0 is 0. Therefore x/0 is NOT DEFINED.

Or plus minus infinity. Or something in between.

Retarded take. It's obviously infinity.

Divide all the eth by zero

May I ask why do you need it to be a number? 🤔

If you have 10 apples, you have 10 apples. If no one has 10 apples, there's not magically infinity apples Incredibly based take.

No, because of limit theorem... Limit of x as 1/x goes to 0 diverges

Is that a floating point zero?

LLMs are already sloppy there is no need to make them even more so. 🤣

No it is not. Division by zero is not a number whether zero or any other.

~ish

In my line of work, we let "=iferror([insert cell], 0)" sort that out

there are only 2 numbers: 0 and 1 and the secret third number is in between ♾️