Saved to my thinkbank.

I understand the formula but not the implications, other than determining whether a given number is rational 😅

The case when x is rational is easier to see as m!x will be an integer from some value of m. Cool formula 🤓

I choose many server to save my images

I can live with it.

I mean … yeah …

Can x at least be reasonable?

ITS ALL GREEK TO ME :)

If X is rational, there will be at least one (actually, infinitely many) Ms for which MX is an integer, and therefore the cosine is either -1 or +1 M! includes many even numbers, therefore the cosine will be +1, not -1 For irrational X, the cosine is always strictly between -1 and +1, and therefor...